1. awk & split 的運用- set time = 12:34:56
- set hr = `echo $time | awk '{split($0,a,":" ); print a[1]}'` # = 12
- set sec = `echo $time | awk '{split($0,a,":" ); print a[3]}'` # = 56
- # = 12 34 56
- set hms = `echo $time | awk '{split($0,a,":" ); print a[1], a[2], a[3]}'`
- ——————————————————————————————————————————
- Q:
- name="76868&5676&435&43526&334&12312312&12321"
- awk 'BEGIN {print split("$name", filearray, "&")}'
- 为什么是1
- 而
- awk 'BEGIN {print split("76868&5676&435&43526&334&12312312&12321", filearray, "&")}'
- 则返回正确的结果,应该是7,有没有人解答一下?
- A:
- 变量引用错误,这样做试试
- awk 'BEGIN {print split('""$name""', filearray, "&")}'
- awk规定引用系统变量必须使用单引号加双引号,即'"$sysvar"'这样的格式,但是split函数也需要双引号来定界,但这个双引号又不能让sh解释,而应留给awk来解释,所以使用了"和"组成的双引号
- split函数的用法
- he awk function split(s,a,sep) splits a string s into an awk array a using the delimiter sep.
- set time = 12:34:56
- set hr = `echo $time | awk '{split($0,a,":" ); print a[1]}'` # = 12
- set sec = `echo $time | awk '{split($0,a,":" ); print a[3]}'` # = 56
- # = 12 34 56
- set hms = `echo $time | awk '{split($0,a,":" ); print a[1], a[2], a[3]}'`
- set hms = `echo $time | awk '{split($0,a,":" ); for (i=1; i<=3; i++) print a[i]}'`
- 实例一:
- cat a
- a:b:c:d:e:f:g:h:i
- 使用awk将该字符串冒号两边的段输出
- cat a |awk -F':' '{split($0,arr,":")}END{for(i=1;i<=NF;i++)printf("%s\n",arr[i])}'
- 输出结果如下
- a
- c
- d
- e
- f
- g
- h
- i
复制代码 2. 大檔案分割小檔案- split -b 1000m ../benzine_all.tgz benzine_all.tgz.p_
复制代码- cat benzine_all.tgz.p_* > benzine_all.tgz
-
- #比對檔案正確 原來與合併是否一致
- md5sum benzine_all.tgz
- 02a53087dd177796def4943f20752098 benzine_all.tgz
-
复制代码 3.
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